(2x+7)(3x^2-16x+16)=0

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Solution for (2x+7)(3x^2-16x+16)=0 equation: 


Simplifying
(2x + 7)(3x2 + -16x + 16) = 0

Reorder the terms:
(7 + 2x)(3x2 + -16x + 16) = 0

Reorder the terms:
(7 + 2x)(16 + -16x + 3x2) = 0

Multiply (7 + 2x) * (16 + -16x + 3x2)
(7(16 + -16x + 3x2) + 2x * (16 + -16x + 3x2)) = 0
((16 * 7 + -16x * 7 + 3x2 * 7) + 2x * (16 + -16x + 3x2)) = 0
((112 + -112x + 21x2) + 2x * (16 + -16x + 3x2)) = 0
(112 + -112x + 21x2 + (16 * 2x + -16x * 2x + 3x2 * 2x)) = 0
(112 + -112x + 21x2 + (32x + -32x2 + 6x3)) = 0

Reorder the terms:
(112 + -112x + 32x + 21x2 + -32x2 + 6x3) = 0

Combine like terms: -112x + 32x = -80x
(112 + -80x + 21x2 + -32x2 + 6x3) = 0

Combine like terms: 21x2 + -32x2 = -11x2
(112 + -80x + -11x2 + 6x3) = 0

Solving
112 + -80x + -11x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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